.bashrc runs python2 instead of python3

Question

I am trying to get a python code to run on boot on the raspberry pi. I added the following line to the .bashrc file at the end of the file:

sudo python3 /home/pi/code.py

The pi uses python2 to run the code instead of python3. Why is this happening and how can I make it run python3?

Thanks

No, I don't want to make python3 my default python version. Thanks though. — user113912, Jan 24 '20 at 20:09
What is the added line to .bashrc meant to do? Call the script at shell start? How do you know it is not working? — joan, Jan 24 '20 at 21:02
.bashrc will not be executed at boot, so whatever is starting your script at boot time using Python2 it is not the line you're looking at. — Dmitry Grigoryev, Jan 27 '20 at 12:21
@bls I see what you're getting at, but Python3 will run a script starting with #!/usb/bin/python2 just fine. — Dmitry Grigoryev, Jan 27 '20 at 12:24

score 1 · Answer 1 · answered Jan 24 '20 at 23:09

.bashrc is NOT intended to run scripts.

It is run each time a non-login interactive shell is started and is used to configure the shell.
~/.bashrc: executed by bash(1) for non-login shells.

There are many ways of running scripts, depending on what you are trying to do. See https://raspberrypi.stackexchange.com/a/47537/8697 for an example.

(There are other problems with the script, but as you shouldn't use it for this purpose, not relevant.)

.bashrc runs python2 instead of python3

1 Answers1