The service error for startup app in a terminal

Question

My Python application needs to run on a Raspberry Pi 3 at startup and in a terminal.

What I did:

1. I created a service screenscript.service in /etc/systemd/system
2. a bash file in /home/pi/mydir/screen.sh
3. a python application in /home/pi/mydir/code/hello.py

code 1, screenscript.service

Description=Terminal Service
After=network.target
[Service]
ExecStart=/home/pi/mydir/screen.sh
[Install]
WantedBy=multi-user.target

code 2, screen.sh

#!/bin/bash
cd home/pi/mydir/code
echo "work dir: '$(pwd)'" >> /tmp/log.log
/usr/bin/lxterminal -e "python /home/pi/mydir/code/hello.py"

code 3, hello.py

import threading

def printit():
  threading.Timer(5.0, printit).start()
  print "Hello, World!"

printit()

My issue:

I want to see 'hello world' continue display in a terminal, when I turn on the raspberry PI power. My service failed $systemctl status screenscript ---> shows loaded, enabled, active failed, code exited.

I can run this line $/usr/bin/lxterminal -e "python /home/pi/mydir/code/hello.py"

Answer 1

At a glance I see some errors. You missed the [Unit] statement before Description=Terminal Service in screenscript.service.

hello.py does not have any indention. This cannot work for a def.

With lxterminal you try to start a graphical program but your service is WantedBy=multi-user.target. This does not provide a graphical environment. You must use WantedBy=graphical.target.

If you want a graphical output you have to specify a display like Environment=DISPLAY=:0. Here is an example: How to make a service to run a python script which includes browser automation.